Light reflects within 2 parallel mirrors? - light reflecting make-up
I thought about this for a while .... If you had to mirror each other and are between 2 perfectly parallel. They reflect the infinite light? I know that light is composed of particles, but only to ask. Thanks
Light Reflecting Make-up Light Reflects Within 2 Parallel Mirrors?
3 comments:
Take two mirrors (perhaps a wall mirror and a mirror) annulled the hand and keep them in parallel. Then use a flashlight on a mirror, the reflection of passing back and forth between the mirrors causes luster. You can count how many ideas and images that are lost in the distance. Photon of light interacts with electrons orbiting atoms and molecules that make up the glass and reflective surfaces of mirrors. Most of the photons pass through clear glass, without changes, but some may have lost due to inclusions in the glass. Since the microscopic examination, the reflecting surface is not also true that perhaps the surface of a diamond crystal structure of the reflection is not 100% effective and parallel incident photon can come with many parallel, the distribution of light and Making successive images are increasingly blurred. An ideal mirror would always get the image even further. But nothing in nature is perfect.
No, because it is not perfectly reflecting. But it is possible to close it. I have two parallel mirrors in the room behind me. One is the mirror of a bathroom and one with the bathroom door is a mirror in a closet with sliding door. It's fun to have a laser pointer, and placed between two mirrors. You can create a bit of light when the angle is right.
In theory, no .... secure in practice .... not even close.
Do you know a beam of light caught between the mirrors, which you describe. Real Flat mirrors are silvered on the back. This means that the light traveling through the glass / air twice (round trip) for each reflection.
The light loses about 4% - 5% of its intensity by reflection, as soon loses its ability to reflect and, of course, not forever gone. This does not take into account the errors and irregularities of the surface by the refraction and energy reflected lose. There are also dispersion feet each wavelength of the light of other causes also ineffective.
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